HackerRank Handson - Python - Match Pattern and Replace - Course Id 55195 - Hackerearth Python

 Match Pattern and Replace

Write a function subst which replaces a pattern matching portion with another value. Using subst, replace all the words ROAD with RD in the following 

addr = ['100 NORTH MAIN ROAD', '100 BROAD ROAD APT.', 'SAROJINI DEVI ROAD', 'BROAD AVENUE ROAD']. Use the Test against custom input box to output the result for debugging. Use print(res) to display the output

1. Write a function subst which replaces a pattern matching portion with another value.

2. Using subst, replace all the words ROAD with RD in the following:

addr = ['100 NORTH MAIN ROAD',
  '100 BROAD ROAD APT.',
  'SAROJINI DEVI ROAD',
  'BROAD AVENUE ROAD']

3. Use the Test against custom input box to output the result for debugging

4. Use print(res) to display the output

Expected Output:

['100 NORTH MAIN RD.','100 BROAD RD.APT.','SAROJINI DEVI RD.','BROAD           AVENUE RD.']

Answer:

#!/bin/python3

import sys

import os

import io

import re

# Complete the function below.

def subst(pattern, replace_str, string):

    #susbstitute pattern and return it

    ki=""

    match= pattern.finditer(string)

    for j in match: ki=re.sub('[^A-Z]ROAD',' RD.',j.group(0))

    if ki[-1]!='.':

        ki+='.'

    return ki

def main():

    addr = ['100 NORTH MAIN ROAD',

            '100 BROAD ROAD APT.',

            'SAROJINI DEVI ROAD',

            'BROAD AVENUE ROAD']

            

    #Create pattern Implementation here 

    new_address=[]

    k='RD'

    pattern=re.compile(r'[A-Z0-9 ]+ROAD\s*[A-Z]*.*')

    for i in addr:

        r = subst(pattern, k, i)

        new_address.append(r)

    #Use subst function to replace 'ROAD' to 'RD.',Store as new_address

    return new_address

'''For testing the code, no input is required'''

if __name__ == "__main__":

    f = open(os.environ['OUTPUT_PATH'], 'w')

    res = main();

    f.write(str(res) + "\n")

    f.close()

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